Concept:The sum of a ratio and its reciprocal is always at least 2.Explanation:Let the number of boys be b and girls be g, where both are positive.Then B=gb​ and G=bg​.So B+G=gb​+bg​=bgb2+g2​.By the AM–GM inequality, b2+g2≥2bg, with equality only when b=g.Therefore B+G≥2.Since 2 is greater than 1, B+G is always greater than 1.Answer:Option B: greater than 1.