Concept:Substitute the given value of x into the expression and simplify using algebraic manipulation.Explanation:We have x=a+b2ab.Substitute into x−ax+a+x−bx+b.First term: x−ax+a=a+b2ab−aa+b2ab+a.Combine fractions: numerator becomes a+b2ab+a(a+b)=a+ba2+3ab.Denominator: a+b2ab−a(a+b)=a+bab−a2.Thus x−ax+a=ab−a2a2+3ab=a(b−a)a(a+3b)=b−aa+3b.Second term: x−bx+b=a+b2ab−ba+b2ab+b.Numerator: a+b2ab+b(a+b)=a+b3ab+b2.Denominator: a+b2ab−b(a+b)=a+bab−b2.Thus x−bx+b=ab−b23ab+b2=b(a−b)b(3a+b)=a−b3a+b.Now sum: b−aa+3b+a−b3a+b.Note b−a=−(a−b), so b−aa+3b=−a−ba+3b.Sum becomes −a−ba+3b+a−b3a+b=a−b−a−3b+3a+b=a−b2a−2b=a−b2(a−b)=2.Answer:The value is 2.