Given, Time taken by
(A+B) to fill the tank
=6h Thus, part of tank filled by A + B in
1h=61​ ..... (i)
(if a pipe fills a tank in
x h, then the part of tank filled in
1h=x1​)
Similarly, part of tank filled by (B + C) in
1h.
=101​.....(ii)
And part of tank filled by (C + A) in
1h=152​......(iii)
Now, part of tank filled by (A + B + C) in
1h On adding Esq. (i), (ii), (in), we get
A+B+B+C+C+A =61​+101​+152​ ⇒2A+2B+2C=305+3+4​ ⇒2(A+B+C)=3012​ ⇒(A+B+C)=6012​ ⇒(A+B+C)=51​ Hence, A, B and C all three can fill the tank in 5h
(if a pipe fills
x1​ part of the tank in
1h, then the time taken by the pipe to fill the full tank
=xh )