Subtracting 3x and adding 3 to both sides of 3x−5≥4x−3 gives −2≥x. Therefore, x is a solution to 3x−5≥4x−3 if and only if x is less than or equal to −2 and x is NOT a solution to 3x−5≥4x−3 if and only if x is greater than −2. Of the choices given, only −1 is greater than −2 and, therefore, cannot be a value of x. Choices B, C, and D are incorrect because each is a value of x that is less than or equal to −2 and, therefore, could be a solution to the inequality.