SSC CGL Tier-1 23-Aug-2021 Shift 2 Solved Paper

Total weight of student in Section A =40×45.5=1820kg
Total weight of students in Section B =40×442=1768kg
Weight of two students of Section A shifted to B=48.75×2=97.50kg
Now, students weight in
A=1820−97.50=1722.5kg
and student weight in Section B
=1768+97.50⇒1865.5kg
According to the question,
1865.5−2x=1722.5+2x
⇒‌‌4x=1865.5−1722.5
⇒‌‌4x=143
⇒‌‌x=35.75
So, the average weight of student shifted to A from B=‌

2×35.75

2

=35.75kg.