SSC CPO SI and ASI Model Paper 9

(2) According to the given condition,The base of the isosceles triangle= the base of the parallelogram= x cm
The isosceles triangle isconstructed between the parallelsides of the parallelogramTherefore, the vertical distancebetween the parallel sides is thealtitude of that triangle
Hence, the area of the triangle
=

1

2

×area of parallelogram
Also, area of triangle=

1

2

×base ×height
⇒

1

2

×x×52=832
⇒x=

832

26

=32
Therefore, the other parallel side= 32 cm