Let A, B and C be the vertices of three cones of radiur r each And ‘O’ be the centre of the circle passing through the points A, B and C Radius of the circle OA = OB = OC From AABC, AB = BC = CA = 2 r AABC is a equilateral triangle
AD is ⊥ from A to BC then, CD = r AD = √(AC)2−(CD)2 = √(2r)2−r2 = √3r Now, AO =
2
3
× AD (Since AD is median) AO =
2
3
×√3r =
3
√3
(r) = 1.15 (r) Hence, radius of the circle will be larger then r