Time and Work Practice Test 2 with solutions

Number of days taken by A can do 20% work = 13 days
So, Number of days taken by A
= 13×20×100 = 65 days
Number of days taken by B to complete

6

7

th part of work = 48 days.
So, work can be completed by B in
= 48×

7

6

= 56 days
Number of days taken by C to complete 66

2

3

% work = 42 days
So, number of days taken by C to complete the work
= 42×

3

200

×100 = 63 days
So, B is the most efficient worker among A, B and C.