P1,P2,P3 are three independent events Probability of happening at least one event is 1−[(P1)⋅(P2)(P3)]=1−(1−P1)(1−P2)(1−P3) ∴A is true. If there independent events are A,B andC ∴P(A∪B∪C)=P(A)+P(B)+P(C)−P(A)P(B) −P(A)P(C)−P(B)P(C)+P(A)P(B)P(C) R is also true. ∴A is true and R is true and R is the correct explanation for A.