Let A=​−1a3​25c​b67​​ If A is a symmetric matrix, then AT=A​−12b​a56​3c7​​=​−1a3​25c​b67​​ On comparing both the matrices, we get a=2, b=3 and c=6​abc​bca​cab​​=​236​362​623​​=2(18−4)−3(9−12)+6(6−.36)=28+9−180=−143