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TS EAMCET 19-July-2022 Shift 1 Solved Paper

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Question : 5

Total: 160

If the matrix A=[

1	2	2
2	1	2
2	2	1

] satisfies the matrix equation A2−4A−5I=0, then A−1=

‌
1
5
[
−3 2 2
−2 3 −2
2 2 −3
]
‌
1
5
[
−3 2 2
2 −3 2
2 2 −3
]
‌
1
5
[
−3 2 2
2 −3 2
−2 −2 3
]
‌
1
5
[
−3 2 2
2 −3 2
2 2 3
]

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