TS EAMCET 19-July-2022 Shift 2 Solved Paper

Let CαHh be the 10‌mL of gaseous hydrocarbon that produces 40‌mL of CO2 and 50‌mL of water
So, CaHb+(a+‌

b

4

)O2→aCO2+‌

b

2

H2O
‌10‌mL+‌ excess→‌‌‌0‌‌‌‌0
‌‌‌‌‌0‌‌‌+‌ excess →‌‌10a‌‌5b
Ratio of volume is =10:40:50=1:4:5
All carbon from hydrocarbon is in the CO2. 10‌mL of hydrocarbon produces 40‌mL of CO2. ∴1:4 ratio.
So, 1 mole of hydrocarbon has four moles of carbon.
10‌mL of hydrocarbon produces 50‌mL water. i.e. 1 : 5 ratio.
Each water molecule has 2 moles of H-atom. So, 1 mole hydrogen carbon compound has 10 moles of hydrogen.
∴ The molecular formula of the hydrocarbon is C4H10.