4p orbital has one angular node and three maxima in its radial probability distribution curve As, number of angular node is equal to ' l ' l = azimuthal quantum number l for s=0,l for p=1 l for d=2,l for f=3 So, angular node =1 (in 4p ) Number of radial nodes =n−l−1 For 4p, radial nodes =4−1−1=2 When radial nodes =2, maxima will be ' 3 '. Thus ' 4p′ is correct answer.