1990×2−173×23=1 Multiplying both sides by 11, we have 1990×22−173×253=11 So,x=22 and y=253 is a solution of the equation 1990x−173y=11Hence, statement (1) is incorrect 3x−12y=7 ⇒x−4y=
7
3
Now, for any integral values of x and y, the LHS is an integer. But, RHS is not an integer So, the equation 3x−12y=7 has no solution in integers for x and y. Hence, statement (2) is correct.