UPSC CDS 1 2018 GK Paper

Power dissipation =i2R
Where, I is the current and R is theresistance of wire.
R=P

L

A

P is the resistivity of wire which is material dependent.
P (Al) is greater than p (Cu)
Since, current, length and area of wire is the same, so, power dissipation completely depends on resistivity of material. More the resistivity of material more resistance will be offered to the flow of current and hence, more power dissipation.
Here, power will be dissipated more in Aluminium wire.
Power (Al) > power (Cu)
And given power (Cu) = P
Hence, power (Al) > p
Therefore, the third option is correct.