Given: The top of a tower from two points at distances p and q from the base. The base and on the same straight line are 27∘ and 63∘ respectively Formula Used: tanθ=cot(90∘−θ) tanθ= Perpendicular\/Base cotθ= Base ∕ Perpendicular tanθ=1∕cotθ BC=p and BD=q In triangle ABD : Tan63∘=H∕q Tan27∘=H∕p⇒Cot27=p∕H Now, Tan63∘=Tan(90∘−27∘)=Cot27∘ So, H∕q=p∕H H2=pq H=√pq ∴ Height of the tower is √pq