Given:
1. If
x is directly proportional to
z and
y is directly proportional to
z, then
(x2−y2) is directly proportional to
z2.
2. If
x is inversely proportional to
z and
y is inversely proportional to
z, then (
xy ) is inversely proportional to
z2 Calculation
Case I.
According to the question
x∝z and
y∝z ⇒x=zk and
y=rz where
k and
r are constants
⇒x2=z2k2 and
y2=r2z2 ⇒x2−y2=z2(k2−r2) ⇒x2−y2∝z2 Hence, Case I is correct.
Case II.
x∝z1 and
y∝z1 ⇒xz=k and
yz=r where
k and
r are constants
⇒xz⋅yz=kr ⇒xyz2=kr ⇒xy=z2kr ⇒xy∝z21 Hence, Case II is correct.