Given : p=22n+2+m and q=24n−m n is even natural number Formula used : (Mab)=(Ma)b (Ma+b)=(Ma⋅Mb) Calculations : If p is divisible by 5 , we have ⇒p∕5=(22n+2+m)∕5 Using the formula above ⇒((22)n×22+m)∕5 ⇒(4n×4+m)∕5 When 4 is divided by 5 it leaves - 1 as a negative remainder, so ⇒(−1n×4+m)∕5 n is an even positive number ⇒(1×4+m)∕5 ⇒(4+m)∕5 The least number required for m is 1 ⇒(4+1)∕5=5∕5=1 Also, we have q=24n−m ⇒q=16n−m Since n is an even positive integer. Therefore, (16-m) will always be one factor of q. If m=1 then q=16−1=15 Which is divisible by 5 . ∴ The least value of m such that p, as well as q, is divisible by 5 is 1 .