In order to find the critical points, we have to convert the given inequality into an equation.∴x2−6x−27=0 ⇒(x−9)(x+3)=0 Critical points are 9 and –3 Now test the given inequality by taking points left and right of these points. When x>9 (x−9)(x+3)>0 when x<0 but >−3 (x–9)(x+3)<0 When x<−3 Thus, the given inequality is true for x<−3 or x>9 (x–9)(x+3)>0