Given, quadratic equation is x2−kx+2=0. In a quadratic equation ax2+bx+c=0, if the D=b2−4ac>0, discriminant, quadratic equation will have real and distinct solutions. For x2−kx+2=0 ∴b2−4ac=(−k)2−4(1)(2) =k2−8 Put b2−4ac>0⇒k2−8>0 ⇒k2−(2√2)2>0 ⇒(k−2√2)(k+2√2)>0 ∴k<−2√2 or k>2√2 Hence, the quadratic equation will have real and distinct solutions for k<−2√2 or k>2√2.