What is 4(CP²-AQ²) equal to?

Correct Answer is : 111.39cm2111.39 {cm}²111.39cm2

Correct Answer is : 111.39cm2111.39 {cm}²111.39cm2

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UPSC CDS 2 2021 Math Paper

Question : 58 of 100

Marks: +1, -0

What is

4(CP^{2}-AQ^{2})

equal to?

Solution: 👈: Video Solution

Now, in

\triangle ABQ

AQ^{2}= \; \; AB^{2}+BQ^{2}=(1.6)^{2}+(3.15)^{2}

\left[ \; \text{ from } \; \; \; \text{ Eq. (iv) of question (56) } \right] \;

\; \; =2.56+9.9225

\; \; =12.4825 \mathrm{cm}^{2}

\triangle BCP

CP^{2}=BC^{2}+PB^{2}=(6.3)^{2}+(0.8)^{2}

[from Eq. (ii) of qusestion (56)]

=39.69+0.64

=40.33 \mathrm{cm}^{2}

4(CP^{2}-AQ^{2})

=4[40.33-12.4825]

=4

[27.8475]

=111.39 \mathrm{cm}^{2}

Hence,

4(CP^{2}-AQ^{2})

equal to

111.39 \mathrm{cm}^{2}

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