Given, AB is a diameter of a circle with centre O. Radius OP is perpendicular to AB and Q is any point on PB. Since, chord PB makes ∠BOP at the centre and ∠BAP at A.
∴∠BAP=21​∠BOP [since, angle made by a chord at a point present on the circle is half of the angle made by chord on the centre] ∠BAP=21​×90∘=45∘ Hence, ∠BAP is equal to 45∘.
