Using the above concept Area of square A1=( side )2 A1=(16)2=256cm2 Now, the area of the circular disc A2=
π
4
(14)2=
22
4×7
×142cm2 ⇒A2=154cm2 The area of the remaining part of the plate =A1−A2 ⇒A=(256−154)cm2=102cm2 The weight of 256cm2 plate =128gm The weight of 102cm2 of the plate =