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UPSC CDS 2 2022 Math Paper
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© examsnet.com
Question : 66
Total: 100
A person
X
starts from a place
A
and another person Y starts simultaneously from another place
B
which is
d
k
m
away from
A
. They walk in the same direction.
X
walks at an average speed of
u
k
m
∕
h
r
and
Y
, walks at an average speed of
v
k
m
∕
h
r
. How far will
X
have walked before he overtakes
Y
?
u
d
(
u
−
v
)
v
d
(
u
−
v
)
(
u
d
−
v
d
)
(
u
−
v
)
(
u
d
+
v
d
)
(
u
+
v
)
Validate
Solution:
👈: Video Solution
When two objects move in the same direction, then
Relative speed = S1 - S2
Time
=
Distance
∕
Speed
⇒
t
=
d
∕
(
u
−
v
)
Distance covered by
X
to overtake
Y
,
⇒
d
=
[
(
u
×
d
∕
(
u
−
v
)
]
⇒
d
=
ud
(
u
−
v
)
∴
The required value is
u
d
(
u
−
v
)
.
© examsnet.com
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