Statement-1: n is a natural number When n is odd, a factor of (xn+yn) is (x+y) but, No factor in the case when n is even Statement-2: n is an even natural number We have discussed already when n is even, there is no factor. In this case (xn+yn) will not be divisible by (x+y) ∴ Statement-2 alone is sufficient to answer the question.