Since the HCF of given numbers is the highest common factor of numbers, therefore, numbers are 16a and 16b, where a and b are some natural numbers 16a×16b=7168⇒ab=28. Here, a and b are co–prime to each other. Also, 16a > 60, i.e., a > 3 and 16b > 60, i.e., b > 3. Therefore, the only possible pair for (a, b) can be (4, 7). Numbers are 16×4, i.e., 64 and 16×7, i.e., 112. Sum of numbers =64+112=176