Remember:The sum of exterior angles of any regular polygon of n (n ≥ 3) sides is 360°
Therefore, sum of exterior angles of a regular polygon of m(m ≥ 3) sides = Sum of exterior angles of a regular polygon of n(n ≥ 3) sides = 360°
Hence, statement 1 is incorrect
Remember: Sum of the interior angles of a regular polygon of n sides
=(n−2)×180°Sum of the interior angles of a regular polygon of m sides
=(m−2)×180°For m > n ≥ 3
(m−2)×180°>(n−2)×180°Therefore, the sum of the interiorangles of a regular polygon of m sides is greater than the sum of the interior angles of a regular polygon of n sides.
Sum of the interior angles of a regular polygon of n sides + Sum of the interior angles of a regular polygon of m sides
=(n−2)×180°+(m−2)×180°=(2n+4+2m−4)×90°=(2m+2n−8)×90°
Hence, statement 2 is incorrect.