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UPSC NDA 2 2017 Mathematics Solved Paper
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© examsnet.com
Question : 11
Total: 120
If
A
=
[
4
i
−
6
10
i
14
i
6
−
4
i
]
and
k
=
1
2
i
where
i
=
√
−
1
then kA is equal to
[NDA II 2017]
[
2
+
3
i
5
7
2
−
3
i
]
[
2
−
3
i
5
7
2
+
3
i
]
[
2
−
3
i
7
5
2
+
3
i
]
[
2
+
3
i
5
7
2
+
3
i
]
Validate
Solution:
k
=
1
2
i
=
−
i
2
k
A
=
[
(
4
i
−
6
)
(
−
1
2
)
10
i
(
−
i
2
)
14
i
(
−
i
2
)
(
6
+
4
i
(
−
i
2
)
)
]
=
[
2
+
3
i
5
7
2
−
3
i
]
© examsnet.com
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