Concept:We treat ∣x−3∣ as a non-negative variable t to convert the equation into a quadratic.Explanation:Set t=∣x−3∣, where t≥0.The equation becomes t2+t−2=0.Factorise: t2+t−2=(t+2)(t−1)=0.So t=1 or t=−2.Since t=∣x−3∣≥0, we discard t=−2 and keep t=1.Now ∣x−3∣=1 gives two cases.Case 1: x−3≥0, i.e. x≥3. Then x−3=1 ⇒ x=4.Case 2: x−3<0, i.e. x<3. Then −(x−3)=1 ⇒ x−3=−1 ⇒ x=2.Both x=2 and x=4 are real roots.Sum =2+4=6.Answer:6 (Option D).