The operation can be done = (No token drawn is yellow) or (2 non-yellow token and 1 yellow token) or (1 non-yellow token and 2 yellow token) Non-yellow tokens = 3 + 2 = 5 Ways of selecting of 3 non-yellow tokens out of 5=5C3=10 Ways of selecting of 2 non-yellow tokens out of 5=5C2=10 Ways of selecting of 1 non-yellow token out of 5=5C1=5 Ways of selecting of 2 yellow tokens out of 5=5C2=10 Ways of selecting of 1 yellow token out of 5=5C1=5 ∴ The total number of ways N=10+(10×5)+(5×10) N=10+50+50=110