Here, we have to find the distance of the line 12(x + 6) = 5(y -2) from the point (- 1, 1) The given equation of line can be re-written as: 12x - 5y + 82 = 0 Let P = (-1, 1) ⇒x1=−1 and y1=1 Here, a = 12 and b = - 5 Now substitute x1=−1 and y1=1 in the equation 12x−5y+82=0, we get ⇒|12.x1−5.y1+82|=|−12−5+82|=65 ⇒√a2+b2=√(12)2+(−5)2=13 As we know that, the perpendicular distance d from P(x1,y1) to the line ax+by+c=0 is given by d = |