The mid-point divides a line in the ratio 1 : 1 internally.
∴ The co-ordinates of the midpoint (M) of points (1, 3) and (1, -7) will be: M(
1×1+1×1
1+1
,
1×3+1×(−7)
1+1
)=M(1,−2) The equation of the line parallel to the line 2x−3y−7=0 can be assumed to be k(2x−3y)−7=0. Since this line passes through M(1, -2), we will get: k[2(1)−3(−2)]−7=0 ⇒k(2+6)−7=0 ⇒k=