We have to find the distance of the point (7, 14, 5) from the plane
2x+4y−z=2 Here, the equation of the plane can be re-written as
2x+4y−z−2=0 As we know that, the distance between the point and the plane is given by
|| Here,
x1=7,y1=14 and
z1=5 So, the distance of the given point form the given plane
=|| 2×7+4×14−5−2 |
| √22+(−1)2+(4)2 |
| =|| So, the distance between the plane and the point is
3√21 Hence, option A is the correct answer.