Given: Equation of lines is 4x – 3y + 6 = 0
The given equation can be re-written as:
y=.x+2 By comparing the above equation with y = m ⋅ x + c we get slope of the given line
m1= Option A:
3x+4y−7=0 If equation of the normal is 3x + 4y - 7 = 0 and this equation can be re-written as:
y=−.x+ By comparing the above equation with y = m ⋅ x + c we get slope of the normal
m2=− ∵ The line and normal are perpendicular to each other so the product of their slopes should be - 1.
⇒m1.m2=4∕3.(−3∕4)=−1 So, option A represents the equation of the normal to the given.
Hence, option A is the correct answer.