We have to find the distance of the point (2, 1, 0) from the plane 2x + y + 2z + 5 = 0 As we know that, the distance between the point and the plane is given by |
Ax1+By1+Cz1−d
√A2+B2+C2
| Here, x1=2,y1=1 and z1=0 So, the distance of the given point form the given plane = =|
2×2+1×1+2×0+5
√22+(1)2+(2)2
| =|
10
√9
| So, the distance between the plane and the point is 10/3 units Hence, option C is the correct answer.