Case -I: We can select one boy and one girl from the given children. The number of ways of doing so is: 3C1×2C1=3×2=6 Case -II: We can also select both boys. The number of ways of doing so is: 3C2=3 Therefore, the number of ways of selecting either one girl and one boy or both boys is given by: 6 + 3 = 9 Therefore, the number of ways of selecting two children such that there is at least one boy is 9.