For a number to be divisible by 5 only if the number end with 0 or 5, here the case is 0, hence the unit digit has to be 0. Now, remaining are 3 digits 3, 4 and 8 If the number is between (100 and 1000), the ways =32×1=9 If the number is between (1000 and 10000), the ways =33×1=27 If the number is between (10000 and 100000), the ways =34×1=81 ∴ Total number of ways = 9 + 27 + 81 Total number = 117