The possible cases can be: 1. 4 boys and 4 girls 2. 3 boys and 3 girls 3. 2 boys and 2 girls Ways of selecting of 4 boys out of 4=4C4=1 Ways of selecting of 3 boys out of 4=4C3=4 Ways of selecting of 2 boys out of 4=4C2=6 Ways of selecting of 4 girls out of 6=6C4=15 Ways of selecting of 3 girls out of 6=6C3=20 Ways of selecting of 2 girls out of 6=6C2=15 ∴ Total possible ways N=(1×15)+(4×20)+(6×15) N=15+80+90=185