As we can see above equation is not in proper form of polynomial so first we make it in polynomial form, Multiply by 6 to the both side of power of terms, ⇒(
d2y
dx2
+
dy
dx
)
1
6
×6=(
dy
dx
+x)
1
3
×6 ⇒(
d2y
dx2
+
dy
dx
)1=(
dy
dx
+x)2 ⇒
d2y
dx2
+
dy
dx
=(
dy
dx
)2+2
dy
dx
x+x2[∵(a+b)2=a2+2ab+b2] ⇒
d2y
dx2
+
dy
dx
−(
dy
dx
)2−2x.
dy
dx
−x2=0 Now we can say about the degree and order, Degree = 1 Order = 2