We have x1=1,x2=2,x3=3 and p1=0.3,p2=0.4,p3=0.3 Now, ∑pixi=(0.3×1)+(0.4×2)+(0.3×3) =0.3+0.8+0.9 =2 And, ∑pi(xi)2=(0.3×12)+(0.4×22)+(0.3×32) =0.3+1.6+2.7 =4.6 ∴Var(X)=σ2=∑pi(xi)2−(∑pixi)2=4.6−22=4.6−4=0.6The variance of the distribution is Var(X)=0.6.