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UPSEE 2019 Solved Paper
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© examsnet.com
Question : 45
Total: 150
The potential difference applied to an X-ray tube is
5
k
V
and the current through it is
3.2
m
A
. Then the number of electrons striking the target per second are
5
×
10
6
2
×
10
16
1
×
10
17
4
×
10
18
Validate
Solution:
Given, potential difference,
V
=
5
k
V
and discharge current,
I
=
3.2
m
A
=
3.2
×
10.3
A
As, we know that current,
I
=
n
e
t
where,
n
=
number of electron,
e
=
charge on electron and
t
=
time
⇒
n
=
I
t
e
Putting
t
=
1
s
and
e
=
1.6
×
10
−
19
C
⇒
n
=
3.2
×
10
−
3
×
1
1.6
×
10
−
19
=
2
×
10
16
Hence,
2
×
10
16
electrons are striking the target per second.
© examsnet.com
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