Here, work function ω0=3eV and photon energy E0=2eV As, Einstein's photoelectric equation E0=W0+KE0 So, KE0=E0−W0⇒KE0=2−3=−1eV Since, kinetic energy is a scalar quantity i.e., KE>0, positive. So, the photoelectron does not ejected and KE=0 ∴ Correct option is (d).