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UPSEE Solved Model Paper 3
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© examsnet.com
Question : 49
Total: 150
The de-Broglie wavelength of a particle moving with a velocity 2.25 ×
10
8
m/s is equal to the wavelength of photon. The ratio of kinetic energy of the particle to the energy of the photon is (velocity of light is 3 ×
10
8
m/s)
1/8
3/8
5/8
7/8
Validate
Solution:
K
particle
=
/
2
m
v
2
also λ =
h
m
v
⇒
K
particle
=
1
2
(
h
v
λ
)
.
v
2
=
v
h
2
λ
K
photon
=
h
c
∴
K
particle
K
photon
=
v
2
c
=
2.25
×
10
8
2
×
3
×
10
8
=
3
8
© examsnet.com
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