Given isotherm:
No. of moles of gas = 1
The gas follows Boyle's law.
The given isotherm is between
log10 P vs
log10 V
Now, ideal gas equation is
pV = nRT
where, p = Pressure
V = Volume
n = No. of moles
R - Gas constant
T = Temperature
For 1 mole:
pV= RT (i)
Taking logarithm both sides of equation (i). we get
log10pV =
log10RT log10p+log10V =
log10RT (Since log ab = log a + log b)
log10p = -
log10V+log10RT Comparing above equation with equation of straight line y = mx + c
Thus.
Intercept, c =
log10 RT
Slope, m = -1
Now, from the graph Intercept,
c = 2
Thus,
log10RT = 2
RT =
(10)2 RT = 100
T =
= 1218.03 K
~ 1220 K
Hence, option 'B' is correct