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VITEEE 2009 Solved Paper
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© examsnet.com
Question : 29
Total: 120
A cell in secondary circuit gives null deflection for 2.5m length of potentiometer having 10m length of wire. If the length of the potentiometer wire is increased by 1m without changing the cell in the primary, the position of the null point now is
3.5m
3m
2.75m
2.0m
Validate
Solution:
Here length of potentiometer wire,
l
=
10
m
Resistance of potentiometer wire
R
=
ρ
×
l
A
or
R
=
(
ρ
×
10
A
)
The value of 2.5m length wire
R
'
=
ρ
×
10
A
×
10
×
2.5
⇒
R
'
=
(
2.5
ρ
A
×
10
)
Potential,
V
'
=
I
×
R
'
=
I
(
2.5
ρ
A
×
10
)
Again the length of potentiometer wire is increase by 1m.
Resistance of null position
R
n
=
(
ρ
×
l
11
×
A
)
∴
V
n
=
IR
n
and
V
=
V
'
⇒
I
×
2.5
ρ
A
×
10
=
ρ
×
l
11
×
A
×
I
or
2.5
×
11
10
=
l
=
2.75
m
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