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VITEEE 2009 Solved Paper
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© examsnet.com
Question : 43
Total: 120
Fluorine reacts with dilute NaOH and forms a gaseous product A. The bond angle in the molecule of A is
104°40'
103°
107°
109°28'
Validate
Solution:
2
F
2
+
2
NaOH
dilute
─
─
─
─
─
─
─
─
▶
2
NaF
+
OF
2
(
A
)
↑
+
H
2
O
The structure of 'A'
(
OF
2
)
is as
σ bonds made by O = 2
Due to repulsion between two lone pairs of electrons, its shape gets disorted. Therefore, the bond angle in the molecule is 103°.
© examsnet.com
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