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VITEEE 2010 Solved Paper
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© examsnet.com
Question : 11
Total: 120
A neutral water molecule
(
H
2
O
)
in its vapour state has an electric dipole moment of magnitude
6.4
×
10
−
30
C
−
m
. How far apart are the molecules centres of positive and negative charges?
4 m
4 mm
4
µ
m
4 pm
Validate
Solution:
In a neutral water molecule, there are 10 electrons and 10 protons.
So, its dipole moment
p
=
q
(
2
l
)
=
10
e
(
2
l
)
Hence length of the dipole = distance between centres of positive and negative charges
2
l
=
p
10
e
=
6.4
×
10
−
30
10
×
1.6
×
10
−
19
=
4
×
10
−
12
m
© examsnet.com
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