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VITEEE 2011 Solved Paper
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© examsnet.com
Question : 117
Total: 120
The area enclosed by y = 3x - 5, y = 0, x = 3 and x = 5 is
12 sq units
13 sq units
13
1
2
sq units
14 sq units
Validate
Solution:
Required area =
5
∫
3
(3x - 5) dx
=
[
3
x
2
2
−
5
x
]
3
5
=
[
75
2
−
25
]
-
[
27
2
−
15
]
=
48
2
- 10 = 14 sq units
© examsnet.com
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