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VITEEE 2011 Solved Paper
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© examsnet.com
Question : 79
Total: 120
Compound A and B are treated with dil. HCl separately. The gases liberated are Y and Z respectively. Y turns acidified dichromate paper green while Z turns lead acetate paper black. The compound A and B are respectively.
N
a
2
C
O
3
and NaCl
N
a
2
S
O
3
and
N
a
2
S
N
a
2
S
and
N
a
2
S
O
3
N
a
2
S
O
3
and
N
a
2
S
O
4
Validate
Solution:
Gas (Y)
S
O
2
which can be obtained from
N
a
2
S
O
3
(A) and gas (Z) is
H
2
S
which can be obtained from
N
a
2
S
(B).
This can be easily understood by the following reactions.
N
a
2
S
O
3
(
A
)
+ 2 HCl → 2NaCl +
S
O
2
(
Y
)
+
H
2
O
N
a
2
S
(
B
)
+ 2 HCl → 2NaCl +
H
2
S
(
Z
)
K
2
C
r
2
O
7
+
H
2
S
O
4
+
3
S
O
2
→
K
2
S
O
4
+
C
r
2
(
S
O
4
)
3
+
H
2
O
p
b
(
C
H
3
C
O
O
)
2
+
H
2
S
→
P
b
S
black
↓ +
2
C
H
3
C
O
O
H
© examsnet.com
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