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VITEEE 2012 Solved Paper
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© examsnet.com
Question : 27
Total: 120
Highly energetic electrons are bombarded on a target of an element containing 30 neutrons. The ratio of radii of nucleus to that of Helium nucleus is
(
14
)
1
∕
3
. The atomic number of nucleus will be
25
26
56
30
Validate
Solution:
Using R =
R
0
A
1
∕
3
R
1
R
2
=
(
A
1
A
2
)
1
∕
3
R
R
he
=
(
A
4
)
1
3
(
14
)
1
∕
3
=
(
A
4
)
1
3
⇒ A = 56
So , = 56 - 30 = 26
© examsnet.com
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